Question

ABC is an isosceles triangle with AB=AC. Altitudes are drawn to the sides AB and AC from vertices C and B respectively. One Altitude CF is found to be 4cm . If BC = 5cm . Find EC, where BE is Altitude to side AC.

4cm
5cm
3cm
None of these

please tell correct answer with correct explanation its urgent plz..​

Answer 1

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Answer 2

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ABC is an isosceles triangle with AB = AC. Altitudes are drawn to the sides AB and AC from vertices B and C. One altitude CF is found to be 4 cm and BC = 5 cm.

Then in triangle BFC the angle BFC =90

Then BF²- BC²- CF²= (5)²-(4)²= 9= BF= 3

In triangle BEF & triange BFC are similler

Then EC=BF=3