ABC is an isosceles triangle with AB=AC altitudes drawn to sides AB and AC from vertices C and B respectively. one altitude CF is found to be 4cm. if BC =5cm. find EC where BE Is altitude to side AC.
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ABC is an isosceles triangle with AB = AC. Altitudes are drawn to the sides AB and AC from vertices B and C. One altitude CF is found to be 4 cm and BC = 5 cm.
Then in triangle BFC the angle BFC =90
Then BF
2
=BC
2
−CF
2
=(5)
2
−(4)
2
=9⇒BF=3
In triangle BEF & triange BFC are similler
Then EC=BF=3
Step-by-step explanation:
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