Question

ABC is an isosceles triangle with AB=AC altitudes drawn to sides AB and AC from vertices C and B respectively. one altitude CF is found to be 4cm. if BC =5cm. find EC where BE Is altitude to side AC.​

Answer 1

Answer:

Step-by-step explanation:

ABC is an isosceles triangle with AB = AC. Altitudes are drawn to the sides AB and AC from vertices B and C. One altitude CF is found to be 4 cm and BC = 5 cm.  

Then in triangle BFC the angle BFC =90

Then$BF^{2}$ =BC^2  −CF^2  =(5)^ 2 −(4)  ^2  =9⇒BF=3

In triangle BEF & triangle BFC are similar  

Then EC=BF=3

Answer 2

Answer:

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