Question

ABC is an isosceles triangle with AB = AC and AD is

Answer 1

median from the vertex A to base BC

Answer 2

We have

AB=AC

⇒∠B=∠C

As AD is altitude, hence

∠ADB=∠ADC=90∘

Three pairs of equal parts in △ADB and △ADC are

AB=AC

∠B=∠C

∠ADB=∠ADC

As two paris of angles in △ADB and △ADC are

equal, hence the third pair will also be equal

∠DAB=∠DAC

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