Question

ABC is an isosceles triangle with AB = AC and AD is one of its altitudes. Show that ∆ADB is congruent of ∆ADC.​

Answer 1

Step-by-step explanation:

In ∆ADB & ∆ADC

<ADB=<ADC= 90 degree (AD Altitude)

AB=AC Given

AD = Common Side

Hence ∆ADB is congruent to ∆ADC by (RHS) Congruency.