Question

ABC is an isosceles triangle with AB=AC and BC =16 cm and perpendicular AD from A on BC=6 cm. find the area of the triangle ABC. also, find the length of the perpendicular from B on AC.

Answer 1

Area of ∆ = 1/2*Base*height

AS, BC=16 AND AD=6

In this ,Area of ∆ABC=1/2*16*6=48

Now, length of ∆ perpendicular from B on AC

(AD)²+(CD)²=AC²

6²+8²=100

AC=10

Now, we know area = 48

1/2*AC*height=48

1/2*10*height=48

Height=48/5=9.6cm