ABC is an isosceles triangle with AB = AC and BD and CE are its two medians. Show that BD = CE . OR
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Answer:
Given:-
AB = AC
Also , BD and CE are two medians
Hence ,
E is the midpoint of AB and
D is the midpoint of CE
Hence ,
1/2 AB = 1/2AC
BE = CD
In Δ BEC and ΔCDB ,
BE = CD [ Given ]
∠EBC = ∠DCB [ Angles opposite to equal sides AB and AC ]
BC = CB [ Common ]
Hence ,
Δ BEC ≅ ΔCDB [ SAS ]
BD = CE (by CPCT)
Step-by-step explanation:
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