Question

ABC is an isosceles triangle with AB =

AC and BD and CE are its two medians.

Show that BD = CE.​

Answer 1

Step-by-step explanation:

the explanation is given above

Answer 2

Answer:

A simpler way:

In ∆ABC,

AB = AC (given)

=> <ABC = <ACD (opposite sides are equal)

In ∆EBC and ∆DCB,

BC = BC (common side)

<EBC = <DCB ( <ABC = <ACB)

BE = DC (E & D are mid points on AB & AC)

=> ∆EBC is congruent to ∆DCB (by SAS

criteria)

=> BD = CE ( by c.p.c.t ) ( proved! )