Question

ABC is an isosceles triangle with AB=AC and BD, CE and its two median. show that BD=CE.Q is a point on the side of s r of a triangle pqr such that PQ equal to p r prove that p s greater than PQ ​

Answer 1

prove triangle AEC and triangle ADB ..from there u get the ratio of sides to be 1 and so the median EC and BD are equal

Answer 2

For triangle ABC,

BE=CD(half of the equal side-AB AND BC are equal)- -eq(1)

angle ABC=angle ACB -eq(2)

BC=BC(common side). -eq(3) So,triangle EBC is congruent to triangle DCB.(by SAS axiom)

Therefore BD=CE(cpct).

What is the diagram of second triangle?