Question

ABC is an isosceles triangle with AB = AC and D is a point on BC such that
AD L BC (see figure), To prove that ZBAD = ZCAD, a student proceeded
as follows
E
(given]
(because AB = AC]
In LABD and GACD, we have
AB = AC
ZB = 2C
and
ZADB = ZADC
Therefore,
LABD = AACD
So,
ZBAD = ZCAD
What is the defect in the above arguments?
[by AAS congruence rule]
[by CPCT]​

Answer 1

Answer:

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Step-by-step explanation:

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