ABC is an isosceles triangle with ab = AC and in the midpoint of base BC state three pairs of equal part in the triangle ABC D and a CD is triangle ABC is equal triangle ACD if so why
pic of the triangle is above
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(a) In triangle ABD and ACD,
AD=AD
AB=AC
BC=CD [D is mid-point at BC]
(b) By using part a of the solution, we get
∴ △ABD≅△ACD ... SSS criterion
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