ABC Is an isosceles triangle with AB
= AC and p is the med holent of
basc BC.
Answers
Answered by
2
Answer:
Given ABC is a trianlge in which AB=AC . P is any point in the interior of the triangle such that angle ABP=ACP
In ΔAPB and ΔAPC,
AB=AC[given]
∠ABP=∠ACP [given]
AP=AP[common]
ΔAPB≅ΔAPC[by SAS congruency criterion]
∴∠PAB=∠PAC [corresponding angles of congruent trianlges]
thus, BP=CP
And AP bisects ∠BAC
Similar questions