ABC is an isosceles triangle with AB = AC
Angle ACB = 55 degrees
Work out angle q, p and r
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it is not clear what q , p and r are ...
If AB = AC, then ∠ACB = ∠ABC = 55°
Hence, ∠CAB = 180- 2 * 55 = 70°
If AB = AC, then ∠ACB = ∠ABC = 55°
Hence, ∠CAB = 180- 2 * 55 = 70°
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