Question

ABC is an isosceles triangle with AB=AC. Draw AP perpendicular BC. Show that angleB = angleC.
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Answer 1

In ∆ APB and ∆ APC,

AB = AC (given)

AP = AP (common side)

Angle APB = Angle APC = 90°

(given, AP perpendicular to BC)

Therefore ∆APB is congruent to ∆APC.

Then , Angle B = Angle C

By C.P.C.T

(corresponding parts of congruent triangles)

Hence , proved.