ABC is an isosceles triangle with AB=AC. draw AP prepedicular to BC to show that
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Suppose ΔADB and ADC
AB = AC
∠ADB = ∠ADC = 90° as they are perpendicular
AD = AD
so,
ΔADB ≅ ΔADC
and thus ∠B = ∠C
AB = AC
∠ADB = ∠ADC = 90° as they are perpendicular
AD = AD
so,
ΔADB ≅ ΔADC
and thus ∠B = ∠C
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