Question

abc is an isosceles triangle with ab = ac, p and q are points on ab =ac respectively such that ap=aq prove that cp=bq​

Answer 1

Answer:

Given AB=AC and AP=AQ then

From the figure PB and QC are equal acc. to your diagram

so, in ∆BQC and ∆CPB

PB=QC (proved above)

angle B = angle C(sinc AB=AC)

BC=CB( common)

∆BQC is congurnt to ∆CPB

therefore, BQ = QC (cpct)

Answer 2

Step-by-step explanation:

Given AB=AC and AP-AQ then

From the figure PB and QC are equal acc. to your diagram

so, in ABQC and ACPB

PB QC (proved above)

angle B = angle C(sinc AB-AC)

BC=CB( common)

ABQC is congurnt to ACPB

therefore, BQ = QC (cpct)

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