Question

ABC is an isosceles triangle with AB = AC. P and Q are points on AB and AC respectively such tha AP = AQ. Prove that CP = BQ.
(Step by step explanation)​

Answer 1

Answer:

Given AB=AC

and AP=AQ

Thus

AB-AP=AC-AQ

[BP=CA ] [from figure ]

now InΔBCP & ΔBCQ

BP = CQ

∠c=∠c [common]

and BC=BC [common]

∴ΔBCP≃ΔBCQ [SAS congruency]

now

[BQ=CP] [corresponding parts of congruent triangles]

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Answer 2

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