Question

ABC is an isosceles triangle with ab is equal to AC and D is a point On AC such that BC square is equal to AC into CD prove that BD is equal to BC

Answer 1

Given in ΔABC, AB = AC
D is a point on AC such that BC2 = AC × AD

In ΔABC and ΔBDC

∠C = ∠C (Common angle)
∴ ΔABC ~ ΔBDC [By SAS similarity criterion]
[Since triangles are similar, corresponding sides are proportional]

From (1) and (2), we get

∴ BC = BD

Answer 2

Answer:

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