Question

Abc is an isosceles triangle with ac=bc circumscribed about a circle

Answer 1

Answer:

As tangents drawn from an external point to a circle are equal in length

So, therefore, we get, AP=AQ (tangents from A) 1)

BP=BR (tangents from B) 2)

CQ=CR(tangents from C) 3)

As it is given that ABC is an isosceles triangle with sides AB=AC

Subtracting AP from both sides, we have,

AB-AP=AC-AP

implies AB-AP=AC-AQ (from 1)

BP=BQ

implies BR=CQ (from 2)

implies BR=CR(from 3)

So therefore BR=CR that shows that BC is bisected at the point of contact.

Step-by-step explanation: