ABC is an isosceles triangle with AC=BC.if AB^=2AC^,Prove that ABC is a right triangle
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Hello !
Δ ABC is an isosceles triangle with AC = BC , and AB² = 2AC²
To prove : ∠C = 90°
Proof :-
AB² = 2AC²
= AC² + AC²
= AC² + BC² [ ∵ AC = BC ]
AB² = AC² + BC² ----> (1)
From (1) ,
∠C = 90° [ by converse of Pythagoras theorem ]
Δ ABC is an isosceles triangle with AC = BC , and AB² = 2AC²
To prove : ∠C = 90°
Proof :-
AB² = 2AC²
= AC² + AC²
= AC² + BC² [ ∵ AC = BC ]
AB² = AC² + BC² ----> (1)
From (1) ,
∠C = 90° [ by converse of Pythagoras theorem ]
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Answered by
42
hey
in the question it is given that
AC=BC ------------------(1)
AND AB^ =AB^+2AC^-------------(2)
by substituinv eq 1 in eq 2 we get
AB^=AC^+AC^
THEREFORE.
angle C=90°
(BY CONVSE OF PYTHAGORAS THEOREM )
HOPE THIS HELPS YOU
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