ABC is an isosceles triangle with AC =BC. If AB=2AC, prove that ABC is a right triangle
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Hii
Here is your answer -
Δ ABC is an isosceles triangle with AC = BC , and AB² = 2AC²
To prove : ∠C = 90°
Proof :-
AB² = 2AC²
= AC² + AC²
= AC² + BC² [ ∵ AC = BC ]
AB² = AC² + BC² ----> (1)
From (1) ,
∠C = 90° [ by converse of Pythagoras theorem ]
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