∆ABC is an isosceles triangle with AC = BC. If AB2 = 2AC2, prove that ΔABC is a right triangle.
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Answer:
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Step-by-step explanation:
The required condition for right triangle ΔABC is AB²=AC²+BC².
From the question, we are given AB²=2AC².
We need to split 2AC² to solve question.
If we split 2AC², we have AB²=AC²+AC².
Then by the given condition AC=BC, we have AC²=BC².
Therefore, AB²=AC²+BC², therefore, ΔABC is a right triangle.
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Answer:
AB2=2AC2
AB2=AC2+AC2
AB2=AC2+BC2
therefore by converse of phythagoras
b=90
Step-by-step explanation:
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