Math, asked by shumanpaul9670, 1 year ago

abc is an isosceles triangle with AC=BC if AB2 =2AC2 prove that ABC is a right triangle











Answers

Answered by skhadloya60
11

AB2=2AC2

AB2=AC2+AC2

AB2=AC2+BC2

therefore by converse of phythagoras

b=90

ABC is isoceles


skhadloya60: sorry for lack of figure
Answered by Anonymous
4

Answer:

The required condition for right triangle ΔABC is AB²=AC²+BC².

From the question, we are given AB²=2AC².

We need to split 2AC² to solve question.

If we split 2AC², we have AB²=AC²+AC².

Then by the given condition AC=BC, we have AC²=BC².

Therefore, AB²=AC²+BC², therefore, ΔABC is a right triangle

Step-by-step explanation:

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