Question

∆ABC is an isosceles triangle with AC = BC. If AB²= 2AC², then the triangle is ​

Answer 1

EXPLANATION:

In ΔABC,

In ΔABC,It is given that AC = BC and AB2 = 2 AC2

In ΔABC,It is given that AC = BC and AB2 = 2 AC2⇒ AB2 = AC2 + AC2

In ΔABC,It is given that AC = BC and AB2 = 2 AC2⇒ AB2 = AC2 + AC2⇒ AB2 = AC2 + BC2 [Since AC = BC]

In ΔABC,It is given that AC = BC and AB2 = 2 AC2⇒ AB2 = AC2 + AC2⇒ AB2 = AC2 + BC2 [Since AC = BC]As the above equation satisfies Pythagoras theorem, we can say that

In ΔABC,It is given that AC = BC and AB2 = 2 AC2⇒ AB2 = AC2 + AC2⇒ AB2 = AC2 + BC2 [Since AC = BC]As the above equation satisfies Pythagoras theorem, we can say that ⇒ ∠ACB = 90°

In ΔABC,It is given that AC = BC and AB2 = 2 AC2⇒ AB2 = AC2 + AC2⇒ AB2 = AC2 + BC2 [Since AC = BC]As the above equation satisfies Pythagoras theorem, we can say that ⇒ ∠ACB = 90°Therefore, ΔABC is a right triangle.

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