Question

ABC is an isosceles triangle with AC= BC
${ab}^{2} = 2 {ac}^{2}$
prove that it is right angle triangle​

Answer 1

Explanation:

Hey mate

I will help,

Its too easy

AB=BC.........( Given)

${ab}^{2} = 2 {ac}^{2} \\ {ab}^{2} = {ac}^{2} + {ac}^{2} \\ {ab}^{2} = {bc}^{2} + {ac}^{2}$

Hence. It's a Pythagoras theorem

And we know Pythagoras theorem is apply only for right angled triangle

Therefore,

Triangle abc is right angled triangle

Answer 2

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Given

AC = BC

Now,

ab² = 2ac²

ab² = ac² + ac²

ab² = bc² + ac²

This is Pythagoras Theorem

Since, Pythagoras theorem is applied so it is a right angled triangle.

Thank you! ❤