ABC is an isosceles tringle with AB is equal to AC draw AP perpendicular BC so that angle B is equal to angle C
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Given :- AB = AC and AP perpendicular to BC.
Prove :- angle B = angle C.
Proof :- In triangle ABP and triangle ACP,
AB = AC (given)
AP = AP (Common)
BP = CP (P is perpendicular to BC)
By SSS Congruent Property,
triangle ABP congruent to triangle ACP.
By CPCT,
Angle B = Angle C
HENCE PROVED.
HOPE IT HELPS YOU....
Prove :- angle B = angle C.
Proof :- In triangle ABP and triangle ACP,
AB = AC (given)
AP = AP (Common)
BP = CP (P is perpendicular to BC)
By SSS Congruent Property,
triangle ABP congruent to triangle ACP.
By CPCT,
Angle B = Angle C
HENCE PROVED.
HOPE IT HELPS YOU....
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0
what should we find here.I think ur question is in incomplete
Please rechech it
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