Question

∆ABC is an isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height AD from A to BC is 6 cm. Find the area of ∆ABC. What will be the height from C to AB? iam put mark as brainlist​

Answer 1

Answer:

7.2 cm

Explanation:

In ΔABC, AD=6cm and BC=9cm

Area of triangle=

2

1

×base×height=

2

1

×BC×AD=

2

1

××6=27 cm

2

Again, Area of triangle=

2

1

×base×height=

2

1

×AB×CE

⇒27=

2

1

×7.5×CE

⇒ CE=

7.5

27×2

⇒ CE=7.2cm

Thus, height from C to AB i.e., CE is 7.2cm