∆ ABC is an isosceles with AB=AC= 7.5 cm and BC=9cm. The height AD from A to BC, is 6cm. Find the area of ∆ABC. What will be the height from C to AB i.e., CE?
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Answered by
24
Answer:
Area of ∆ABC=½×b×h
=> ½×BC×AD
=> ½×9×6
=> 27cm
Area of ∆ABC=½×b×h
=> ½×AB×CE
27=> ½×7.5×CE
27×2=>CE
___
7.5
7.2cm=>CE
Answered by
6
Answer:
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Step-by-step explanation:
Area of ∆ ABC = 1/2 × Base × Height
= 1/2 × BC × AD
= 1/2 × 9 × 6
= 27 cm²
Area of ∆ ABC = 1/2 × Base × Height
= 1/2 × AB × CE
27 cm² = 1/ 2 × 7. 5 × CE
CE = 7.2 CM
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