Question

ABC is an isoscles traingle in which AB= AC and AD is the altitude from a to the base BC. Prove that BD= DC.

Answer 1

ab =ac
angle b= angle c
90=90
by aas
rule two triangles r congruent and by cpct we can say that bd=dc

Answer 2

Hey dear friend,

Taking ∆ABD and ∆ACD

AB=AC {Given)
angleABD=angleACD (angle opp. to)
(equal side are )
(equal)
Angle ADB=Angle ADC (as there is an
( 90° angle on D)

So, by AAS congruency ∆ABD=~∆ACD

So, by CPCT. BD=DC

perfectly fine pure correct answer
hope it helps you mark me as brainliest and follow me