Question

ABC is an isoscles triangle with AB=AC. draw AP perpendicular to BC to show that angle B = angle C​

Answer 1

Answer:

In ΔABP and ΔACP,

∠APB=∠APC (Both equal to 90°)

AB=AC [∵ΔABC is an isosceles triangle.]

AP=AP (Common Side)

By R.H.S. criterion of congruence,

△ABP≅△ACP

⇒∠B=∠C (CPCT)

Answer 2

Answer:

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