Question

ABC is an issiscles triangle in which altitudes
BE and CT are drawn to equal side AC and AB
respectively Show that these
altitudes an equal​

Answer 1

Step-by-step explanation:

Here we use ASA congruenceASA(angle side angle):Two Triangles are congruent if two angles and the included side of One triangle are equal to two angles & the included side of the  other triangle.

Given:

ΔABC is an isosceles∆ with AB = AC, BD and CT are altitudes.

To prove:

BD = CT

Proof:

In ΔATC and ΔADB

∠A = ∠A. (Common)

∠ATC = ∠ADB (each 90°)

AB = AC (Given)

Therefore, ΔAEC ≅ ΔADB[by AAS congruence rule]

Thus, BD = CT (by CPCT)

Hence , altitudes BD & CT are equal.

HOPE THIS ANSWER WILL HELP YOU...

@ansika .

#follow .

Answer 2

$\huge \boxed{ \bf \red{answer}}$

Here we use ASA congruenceASA(angle side angle):Two Triangles are congruent if two angles and the included side of One triangle are equal to two angles & the included side of the other triangle.

Given:

ΔABC is an isosceles∆ with AB = AC, BD and CE are altitudes.

To prove:

BD = CE

Proof:

In ΔAEC and ΔADB

∠A = ∠A. (Common)

∠AEC = ∠ADB (each 90°)

AB = AC (Given)

Therefore, ΔAEC ≅ ΔADB[by AAS congruence rule]

Thus, BD = CE (by CPCT)

Hence , altitudes BD & CE are equal.

HOPE THIS ANSWER WILL HELP YOU...