Math, asked by ashok4971, 10 months ago

ABC is an issoseles triangle and angle B = 90°. Then show that AC² = 2 times AB

Answers

Answered by Anonymous

QUESTION :-

SOLUTION :-

Given that,

ABC is an isosceles triangle

angle B = 90°

By Pythagoras theorem

AC² = AB² + BC²

AC² = AB² + AB² (AC = BC)

AC² = 2AB²

Hence Proved

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Answered by anshi60

Correct Question :-

ABC is an issoseles triangle and angle B = 90°. Then show that AC² = 2 AB².

Given -

$ABC \: is \: isosceles \: triangle \: and \: \angle \: B= 90 \degree$

To prove -

AC² = 2AB²

Solution :-

$In\: \triangle \: ABC \: , \angle \: B \: = 90 \degree$

Since, ∆ABC is an isosceles triangle

therefore, AB = BC

We know that

Two sides of isosceles triangle are equal.

By using Pythagoras theorem

Sum of square of two sides of a triangle is equal to square of third side.

In right triangle ABC

AC² = AB² + BC²

AC² = AB²+ AB² (since , AB = BC)

AC² = 2AB²

Hence proved

Attachments:

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ABC is an issoseles triangle and angle B = 90°. Then show that AC² = 2 times AB​

Answers

QUESTION :-

SOLUTION :-

Correct Question :-

Given -

To prove -

Solution :-

We know that

By using Pythagoras theorem

In right triangle ABC

Hence proved

ABC is an issoseles triangle and angle B = 90°. Then show that AC² = 2 times AB