ABC is an right angled isoscele right angle atC.prove that AB^2 = 2AC^2
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Step-by-step explanation:
given that ΔABC is an isosceles triangle right angled at C.
In ΔACB, ∠C = 90°
AC = BC (Given)
AB2 = AC2 + BC2 ([By using Pythagoras theorem]
= AC2 + AC2 [Since, AC = BC]
AB2 = 2AC2
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