Question

ABC is aright angle triangle . angle abc =90 degree , AC= 25 and AB = 24 .calculate the area of a triangle ABC​

Answer 1

Answer:

according to Pythagoras theorem AB^2 + BC^2= AC^2

therefore BC^2= 49 BC=7

area = 7*24/2=84

Answer 2

Answer:

84

Step-by-step explanation:

Given,

angle ABC = 90°, AC= 25 & AB = 24

therefore, BC =

$\sqrt{ {25}^{2} - {24}^{2} }$

therefore, BC =

$\sqrt{625 - 576 }$

therefore, BC =

$\sqrt{49}$

therefore, BC = 7

So, the area of the triangle ABC =

$\frac{1}{2} \times 24 \times 7$

= 12×7

= 84