Math, asked by g8ananyabomis, 3 months ago

ΔABC is drawn such that AC=14.2 cm and perpendicular distance of B from AC=3.1 cm. Ravi decides to make one more triangle ΔADC with same base AC such that perpendicular distance of D from AC= 4.5cm. Find the area of the quadrilateral ABCD.
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Answers

Answered by nathpratima16
0

Answer:

ΔABC is drawn such that AC=14.2 cm and perpendicular distance of B from AC=3.1 cm. Ravi decides to make one more triangle ΔADC with same base AC such that perpendicular distance of D from AC= 4.5cm. Find the area of the quadrilateral ABCD.

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