ABC is equilateral triangle of side 2a then the length of one of its altitude is
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Answer:
√3a units
Step-by-step explanation:
We know that, in a right triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides.
In the equilateral ΔABC, we see that AB = BC = CA = 2a [From the figure shown above]
AD ⊥ BC [Construction]
⇒ BD = CD = 1/2 BC = a [Since the perpendicular drawn from a vertex to the opposite side bisects the opposite side in an equilateral triangle]
In ΔADB, using pythagoras theorem,
AB2 = AD2 + BD2
AD2 = AB2 - BD2
AD2 = (2a)2 - a2
AD2 = 4a2 - a2
AD2 = 3a2
AD = 3a
⇒ AD = √3a units
Similarly, we can prove that, BE = CF = √3a units
Summary:
If ABC is an equilateral triangle of side 2a, then each of its altitudes are AD = BE = CF = √3a units.
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