Math, asked by esha538, 8 hours ago

ABC is equilateral triangle of side 5√3 cm.
find the length of its median.

Answers

Answered by bhavikagoyal08
0

Answer:

\sqrt{225}cm

Step-by-step explanation

As the side's length  = 5\sqrt{3}

so median will be =(5\sqrt{3} )^{2}  - \frac{(5\sqrt{3} )^{2} }{2^{2} }

=> 45 - 22.5= x^{2} \\\sqrt{22.5}= x

Answered by TheEggHead
0

Answer: 1.5 cm

Step-by-step explanation:

Side = 5√3 cm

Area of equi. triangle = \frac{\sqrt{3} }{4}s^{2}

=> \frac{\sqrt{3} }{4}(5\sqrt{3}) ^{2}

=> \frac{\sqrt{3} }{4} × 25 × 3

=>\frac{75\sqrt{3} }{4} cm²

Area of triangle = \frac{1}{2} × b × h = \frac{75\sqrt{3} }{4}

=> \frac{75\sqrt{3} }{4} = \frac{1}{2} × 5√3 × h

=> h = \frac{75\sqrt{3} }{4} × \frac{2}{5\sqrt{3}} = 3/2 cm = 1.5 cm

Hope it helps! Have a good day! Please mark as brainliest answer! :D

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