∆ABC is inscribed in a circle. TB and TC are
tangents to the circle. AB |ICT and angle T =40°. Find
angle ACB.
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Answer:
According to the alternate segment theorem, angle between a tangent and a chord through a point of contact is equal to the angle in the alternate segment.
⟹∠BCX=∠BAC=40
∘
Given BD∥XY
⟹∠DBC=∠BCX=40
∘
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