∆ABC is inscribed in a circle with centre Osegment AE is a diameter. The tangent drawn at point E intersects the line AB atpoint X and line AC at point Y. show that ∆ABC ~∆AYX.
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Step-by-step explanation:
line AB is proportional to the line AX
lineAC is proportional to the line AY
line BC is proportional to the line XY
the values of an angles donot vary with the lengths of the sides of the triangle, if the angles remains same.
here angles don't change
so, by property AAA
we can say that both triangles are similar.
therefore∆ABC ~∆AYX
I hope this helps you.
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