△ABC is isosceles. AB=AC and AD⊥BC. Prove that ∠B=∠C.
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Answer:
Step-by-step explanation:
In △ABP and △ACP
AB=AC (Given)
∠APB=∠APC (Each equal to 90°)
AP=AP (Common)
Therefore, by RHS congruence rule, △ABP≅△ACP
Hence, ∠B=∠C (Corresponding parts of congruent triangles are equal)
hope, this will help you.
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Answered by
0
Answer:
Here , c.p.c.t stands for corresponding part of congruent triangles.
And equation 1 states that AD is perpendicular to BD .
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