ABC is isosceles triangle and angle B = angle C, AD is perpendicular from A on BC, prove that triangle ABD congruence triangle ACD hence show that D is the mid-point of BC
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In triangle ABD and ACD
angle B=angle C
AD=AD. (common)
and,
AB = AC (as triangle is isosceles triangle)
hence, by SAS rule
triangle ABD =~ triangle ACD.....
PLEASE MARK AS BRAINLIEST....
angle B=angle C
AD=AD. (common)
and,
AB = AC (as triangle is isosceles triangle)
hence, by SAS rule
triangle ABD =~ triangle ACD.....
PLEASE MARK AS BRAINLIEST....
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