∆ABC is isosceles with AB=7.5 and BC=9cm. the height AD from A to BC is 6cm .find the area of ∆ABC . what will be the height from C to i.e CE?
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Step-by-step explanation:
Area of ∆ ABC = 1/2 × Base × Height
= 1/2 × BC × AD
= 1/2 × 9 × 6
= 27 cm²
Area of ∆ ABC = 1/2 × Base × Height
= 1/2 × AB × CE
27 cm² = 1/ 2 × 7. 5 × CE
CE = 7.2 CM
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