Question

ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm . The height

AD from A to BC, is 6 cm. Find the area of ABC. What will be the height from C

to AB i.e., CE?

Answer 1

Answer:

ANSWER

The perpendicular is the height.

The perpendicular divides the base into two equal parts.

BD=DC=4.5 cm

then area =

2

1

×6×9=27 cm

2

when perpendicular drawn from C

then height =h base =7.5 cm

⇒

2

1

×h×7.5=27

⇒h=7.2 cm

Answer 2

Answer:

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Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM

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