Question

∆ABC is isosceles with AB= AC ,line segment AD bisects ∟A and meet the base BC at D .
Prove that ∆ ABD ≅ ∆ ACD

Answer 1

Step-by-step explanation:

Given:         AB=AC

To Prove:    ∆ABD ≅ ∆ACD              

We have,

AB = AC (Given)

∠BAD = ∠CAD (AD bisects ∠BAC)

AD = AD(Common)

By SAS Congruence Rule

∆ ABD ≅ ∆ ACD

Hence Proved