Question

∆ABC is isosceles with AB=Ac=s. and Bc=8cm. What will be the height from c to AB that is overline CE ? If the height AD from A to BC overline 1s^ prime 4.5cm Find the area of ∆ ABC​

Answer 1

Step-by-step explanation:

In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=

2

1

×base×height=

2

1

×AB×AC

=

2

1

×5×12=30cm

2

Now, in ΔABC,

Area of triangle ABC=

2

1

×BC×AD

⇒30=

2

1

×13×AD

⇒ AD=

13

30×2

=

13

60

cm.

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