Question

∆ABC is isosceles with AN=AC=7.5cm and BC=9cm. The height of AD from A to BC is 6cm. Find the area of ∆ABC. What will be the height from C to AB I.e., CE?​

Answer 1

Answer:

In ΔABC, AD=6cm and BC=9cm

Area of triangle=

2

1

×base×height=

2

1

×BC×AD

=

2

1

×9×6=27 cm

2

Again, Area of triangle=

2

1

×base×height=

2

1

×AB×CE

⇒27=

2

1

×7.5×CE

⇒ CE=

7.5

27×2

⇒ CE=7.2cm

Thus, height from C to AB i.e., CE is 7.2cm

Answer 2

Answer:

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Step-by-step explanation:

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × BC × AD

= 1/2 × 9 × 6

= 27 cm²

Area of ∆ ABC = 1/2 × Base × Height

= 1/2 × AB × CE

27 cm² = 1/ 2 × 7. 5 × CE

CE = 7.2 CM

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