Question

ΔABC is rectangle at C prove that

Answer 1

In Δbcd is aright tiangle right angled at b=bd2 +bc2 =cd2....eq 1.

Answer 2

According to given sum,

In triangle ACE,

AE^2 =AC^2+CE^2 ..............¡

In triangle BCD,

BD^2=DC^2+CB^2...............¡¡

Adding equation i & ii

AE^2+BD^2= AC^2+CE^2+DC^2+BC^2

AE^2+BD^2=(AC^2+BC^2)+(CE^2+DC^2)

AE^2+BD^2=AB^2+DE^2 .

:-)Hence proved.

Hope it helps u.