Math, asked by talanchaya5, 5 months ago

∆ABC is right angle at C andCD AB. If<A=55°, find (i) <ACD (ii) <BCD (iii) <CBD

Answers

Answered by nithya5018

1

Answer:

ACD-180-65=105°....property of triangle BCD-105°

Step-by-step explanation:

I think

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