△ABC is right angled at A. AD is altitude with D is on BC. DE is altitude with
E on AC. If AE = 36 and area of △ADE = 864, find AB. PLZ HELP I WILL MARK YOU BRAINLIEST IF YOU GIVE CORRECT ANS.
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Given that
Δ
A
B
C
is right angled and
A
D
is drawn perpendicular to
B
C
. So
∠
B
A
C
is right angle.
Given
B
C
=
9
c
m
and
B
D
=
4
c
m
→
C
D
=
B
C
−
B
D
=
5
c
m
In
Δ
A
B
C
and
Δ
A
B
D
∠
A
B
D
=
∠
A
B
C
∠
A
D
B
=
∠
B
A
C
=
right angle
∠
B
A
D
=
∠
A
C
D
(
remaining
)
So
Δ
A
B
C
and
Δ
A
B
D
are similar
Hence
A
B
B
C
=
B
D
A
B
⇒
A
B
2
=
B
D
×
B
C
=
4
×
9
=
36
⇒
A
B
=
√
36
c
m
=
6
c
m
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