Math, asked by itzroyaljatti, 14 hours ago

△ABC is right angled at A. AD is perpendicular to BC. If AB = 5cm, BC = 13cm and AC = 12cm. Find the area of \triangle△ ABC. Also find the Length of AD.


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Answers

Answered by gfake3596
0

Step-by-step explanation:

Answer

In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=

2

1

×base×height=

2

1

×AB×AC

=

2

1

×5×12=30cm

2

Now, in ΔABC,

Area of triangle ABC=

2

1

×BC×AD

⇒30=

2

1

×13×AD

⇒ AD=

13

30×2

=

13

60

cm.

Answered by Anonymous
23

Answer:

In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=21×base×height=21×AB×AC

=21×5×12=30cm2

Now, in ΔABC,

Area of triangle ABC=21×BC×AD

⇒30=21×13×AD

⇒ AD=1330×2=1360cm.

Step-by-step explanation:

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